Aptitude - Questions & Answers

Aptitude - Calendar Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Calendar. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - What was the week's day on fourth June, 2002?

Answer : A

Explanation

4Th.june, 2002 = (2001 years+ period from 1.1.2002 to. 4.6.2002.
Odd days in 1600 years = 0
Odd days in 400 years = 0
Odd days in 1 customary years = 1

Odd days in 2001 years = (0+0+1)=1

Jan + Feb. +March +April+ May +June
(31 + 28 +31+ 30 + 31 +4 = 155 days=22 weeks +1 day = 1 odd days

Aggregate no. of odd days = (1+1) = 2
∴ required day is Tuesday.

Q 2 - Jan.1, 2007 was Monday. What day of the week lies on Jan 1, 2008?

Answer : B

Explanation

The year 2007 is a common year.
So, it has 1 odd day.

First day of the year 2007 was Monday.
First day of the year 2008 will be 1 day past Monday.
Subsequently, it will be Tuesday.

Q 3 - On eighth Dec, 2007 Saturday falls. What was the day of the week would it say it was on eighth dec, 2006?

Answer : D

Explanation

The year 2006 is a common year. 
Along these lines, it has 1 odd day.
In this way, the day on eighth Dec, 
2007 will be 1 day past the day.

On eighth Dec, 2006.
Yet, eighth Dec,2007 is Saturday.
∴ eighth Dec, 2007 is Friday.

Q 4 - The calendar for the year 2007 will be the same for the year:

Answer : D

Explanation

Count the number of odd days from the year 2007 onwards,
to get the sum equal to 0 odd days.


years
2007
2008
2009
2010
2011
2012
2013
2014
2015
2016
2017


Odd Days
1
2
1
1
1
2
1
1
1
2
1


Sum =14 odd days=0 odd day.
∴ Calendar for the year 2018 will be the same as for the year 2007.

years	2007	2008	2009	2010	2011	2012	2013	2014	2015	2016	2017
Odd Days	1	2	1	1	1	2	1	1	1	2	1

Q 5 - on what dates of April, 2001 did Wednesday fall?

A - 1st, 8th, 15th, 22nd 29th

B - 2nd, 9th, 16th, 23rd, 30th

C - 3rd, 10th, 17th, 24th

D - 4th, 11th, 18th, 25th

Answer : D

Explanation

We might discover the day on first April, 2001.
First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001)
Odd days in 1600 years =0.
Odd days in 400 year =0.

Jan Feb March April
31 + 28 + 31 + 1 = 91 days =0 odd day.

Aggregate number of odd days= (0+0+0) =0.

On first April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.

Q 6 - What was the week's day on 28th may, 2006?

Answer : D

Explanation

28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006)
Odd days in 1600 years=0.
Odd days in 400 years = 0.

5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days
= 6 odd days.

Jan + Feb. + March + April + May
31 + 28 + 31 + 30 + 28 =148 days.

148 days = (21 weeks+1 day) = 1 odd day
Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day.
 
Given day is Sunday.

Q 7 - The last day of a century can't be:

Answer : C

Explanation

100 years contain 5 odd days.
∴ Last day of first century is Friday. 

200 years contain (5*2) = 3 odd days.
∴ Last day of second century is Wednesday.

300 year contain (5*3) =15=1 odd day.
∴ Last day of third century is Monday.

400 year contain 0 odd days.
∴ Last day of fourth century is Sunday.

The cycle is repeated.
∴ Last day of a century can't be Tuesday or Thursday or Saturday.

Q 8 - Which of the accompanying is not a leap year?

Answer : A

Explanation

The century divisible by 400 is a leap year.
∴ The year 700 is not a jump year.

Q 9 - It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

Answer : C

Explanation

On 31st December,2005 it was Saturday.
Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days.

∴ On 31st December 2009 , it was Thursday.
In this way, on first jan, 2010 it is Friday.

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