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Aptitude - Averages Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Averages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Find the average of the numbers which are as follows : 15, 5, 0, 12, 8
Answer : C
Explanation
Average required = (15+5+0+12+8)/5 = 40/5 = 8
Q 2 - 45 kg weight is the average of A, B and C. if the given condition of weight is 40 kg is the average of A and B while B and C have the average weight is 43 kg. Find out the weight of B?
Answer : C
Explanation
A, B and C have total weight = 45*3 = 135 kg A and B have total weight = 40*2 = 80 kg B and C have total weight = 43*2 = 86 kg ∴ weight of B = (80+86- 135) = 31 kg.
Q 3 - 56 is the mean weight of 120 students in second year. We find that 50 kg is the average of girls and 60 kg is the average of boys weight. Find out the number of boys and girls in second year.
Answer : A
Explanation
If x is the number of boys then the numbers of girls will be (120-x) Total weight of the second year student = 56*120 =6720 For finding the value of boys in second year , we solve the equation such that 60x+50(120-x) = 6720 ⇒ 60x+6000-50x = 6720 ⇒ x = 72 So , the number of boys is 72 and the number of girls is (120-72)=48
Q 4 - Before the period of 10 years, 24years is the average of 4 members family. After two children born, the average age of the family no change if 2 years is the age difference between 2 children then what should be the youngest child age?
Answer : A
Explanation
x is the age of the youngest child. Then, elder son child age = (x+2) years. At the present day average age of 6 members = 24 years. At the present day , some of the ages of 6 members = (24*6)= 144 years. (24*4)+(10*4) +x+(x+2) =144 ⇒ 2x = 6 ⇒ x= 3 At the present time the youngest child have 3 year age old.
Q 5 - 15 is the average weight of 19 students if a new student add then the average weight of the class is 14.8 kg. Find out the weight of the new join student?
Answer : B
Explanation
19 students have total sum of the weight = (15*19) =285 kg. 20 students have total sum of the weight = (14.8*20)= 296 kg. Weight of the new student = 296- 285 = 11 kg.
Q 6 - Find out the number of papers in exams if 63 is the average marks in exams.65 marks will be the average if 20 marks obtained by him in geography and 22 marks in History.
Answer : A
Explanation
let there be n papers. Sum of marks of all papers = 63n 65-63n = (20+2) ⇒ 2n = 22 ⇒ n =11 Hence, its proves that the 11 papers held in exams.
Q 7 - The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers?
Answer - B
Explanation
Sum of the remaining two numbers = (3.95 x 6) - [(3.4 x 2) + (3.85 x 2)] = 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20 Therefore Required average = 9.2⁄2 = 4.6.
Q 8 - In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer - B
Explanation
Required run rate = 282 - (3.2 x 10)⁄40 = 250⁄40 = 6.25.
Q 9 - The average age of 36 students in a group is 14 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years?
Answer - D
Explanation
Age of the teacher = (37 x 15 - 36 x 14) years = 51 years.
Q 10 - 3 years ago. the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is ?
Answer - C
Explanation
Total age of 5 members, 3 years ago = (17 x 5) years = 85 years Total age of 5 members now = (85 + 3 x 5) yrs = 100 years Total age of 6 members now = (17 x 6) years = 102 years Therefore Age of younger child = (102 - 100) = 2 years