The Number of Full Rounds You Have Played - Problem

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int timeToMinutes(char* time) {
    int hours = (time[0] - '0') * 10 + (time[1] - '0');
    int minutes = (time[3] - '0') * 10 + (time[4] - '0');
    return hours * 60 + minutes;
}

int solution(char* loginTime, char* logoutTime) {
    int login = timeToMinutes(loginTime);
    int logout = timeToMinutes(logoutTime);
    
    int count = 0;
    
    // Check all 96 possible rounds (every 15 minutes in 24 hours)
    for (int roundStart = 0; roundStart < 24 * 60; roundStart += 15) {
        int roundEnd = roundStart + 15;
        
        if (logout > login) {  // Same day
            if (roundStart >= login && roundEnd <= logout) {
                count++;
            }
        } else {  // Next day (logout <= login)
            // For next day scenario, we play from login time to end of day,
            // then from start of next day to logout time
            
            // Can we play this round fully?
            // Case 1: Round is after login time (same day portion)
            if (roundStart >= login) {
                count++;
            }
            // Case 2: Round is before logout time (next day portion)  
            else if (roundEnd <= logout) {
                count++;
            }
        }
    }
    
    return count;
}

int main() {
    char loginTime[10], logoutTime[10];
    fgets(loginTime, sizeof(loginTime), stdin);
    fgets(logoutTime, sizeof(logoutTime), stdin);
    
    // Remove newlines
    loginTime[strcspn(loginTime, "\n")] = 0;
    logoutTime[strcspn(logoutTime, "\n")] = 0;
    
    int result = solution(loginTime, logoutTime);
    printf("%d\n", result);
    return 0;
}